PLEASE HELP!! SHOW WORK! <3
Find the area of this figure. Dimensions are in meters.
![PLEASE HELP SHOW WORK lt3 Find the area of this figure Dimensions are in meters class=](https://us-static.z-dn.net/files/d64/1ec6b5e05fda141268b28f113f3b55bc.png)
Answer:
2√46 + 25π/4 ≈ 33.2 . . . . m²
Step-by-step explanation:
The altitude of the triangle is given by the Pythagorean theorem. The right triangle of interest is the one that has 5√2 as its hypotenuse, and a leg of half the base shown. Then the other leg, the altitude of the triangle, is ...
h = √((5√2)² - 2²) = √46
Then the area of the triangle shown is ...
A = (1/2)bh = (1/2)(4)(√46)
A = 2√46
__
The area of the semicircle is given by the formula ...
A = (1/2)πr²
Filling in the radius shown, the area is computed as ...
A = (1/2)π(5√2/2)² = 25π/4
So, the total area of the figure is ...
total area = triangle area + semicircle area
= 2√46 + 25π/4 . . . square meters
≈ 33.2 . . . square meters