Respuesta :
Answer:
[tex]\frac{13}{16}[/tex]
Step-by-step explanation:
To compare the 2 fractions we require them to have a common denominator
Change the denominator of 3 quarters by multiplying numerator and denominator by 4
[tex]\frac{3}{4}[/tex] = [tex]\frac{3(4)}{4(4)}[/tex] = [tex]\frac{12}{16}[/tex]
The fraction with the larger numerator is the greater, that is
[tex]\frac{13}{16}[/tex]
On comparing the two fractions we get [tex]\rm Number_2 > Number_1[/tex] that is:
[tex]\dfrac{13}{16}>\dfrac{3}{4}[/tex] .
Given :
[tex]\rm Number_1 = \dfrac{3}{4}[/tex]
[tex]\rm Number_2 = \dfrac{13}{16}[/tex]
Solution :
The value of
[tex]\dfrac{3}{4}=0.75[/tex]
Now the value of
[tex]\dfrac{13}{16} = 0.8125[/tex]
Clearly we can see that
[tex]\rm Number_2>Number _1[/tex]
[tex]\dfrac{13}{16}>\dfrac{3}{4}[/tex]
For more information, refer the link given below
https://brainly.com/question/16110107
