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Answer:
[tex]\large\boxed{0}[/tex]
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Step-by-step explanation:
We are solving the expression: [tex]\frac{2*(3+(2-1))}{4-(6+2)} -(3-5)[/tex]
Solve:
[tex]\frac{2*(3+(2-1))}{4-(6+2)} -(3-5)\\\\\text{Lets start with the fraction}\\\\\frac{2*(3+(2-1))}{4-(6+2)} -(3-5)\\\\\frac{2*(3+(1))}{4-(8)} -(3-5)\\\\\frac{2*(4)}{-4} -(3-5)\\\\\frac{8}{-4} -(3-5)\\\\-2 -(3-5)\\\\\text{Distrubute the negative to the numbers inside the parenthesis}\\\\-2 -3+5\\\\-5+5\\\\\boxed{0}[/tex]
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