Question

The circle below is centered at the point (4,1) and has a radius of length 2. What is it’s equation?

Answer 1

Answer:

Option B:

$(x-4)^2+(y-1)^2 = 4$

Step-by-step explanation:

Given

Centre = (h,k) = (4,1)

Radius = r = 2

The standard equation of circle is:

$(x-h)^2+(y-k)^2=r^2$

Putting the values of h,k and r

$(x-4)^2+(y-1)^2 = (2)^2\\(x-4)^2+(y-1)^2 = 4$

Hence, the correct option is option B

$(x-4)^2+(y-1)^2 = 4$

Answer 2

Answer:

B

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k ) = (4, 1) and r = 2, hence

(x - 4)² + (y - 1)² = 4 → B