What is the equation of the line that is parallel to the given line and passes trough the point (2,3)?
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Answer:
[tex]y=\frac{-1}{2}x + 4[/tex]
Step-by-step explanation:
First we need to find the slope of the given line, the one that is passing trough the points (-4,0) and (4,-4).
For that, lets use the slope`s equation [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
m= (-4-0) / (4-(-4)) = -1/2
A line that is parallel to this one must have its same slope, so m2= -1/2
Now, lets find the 'y' axis intercept point using the point given: (2,3)
And the equation for lines: y=mx+b
By evaluating (2,3) in the above expression we have:
3=-1/2 * 2 +b
From here, we obtain that b=4
Hence, our line is y=-1/2 * x + 4