Respuesta :
You cannot have a square of a negative so you have to see what values of x would not produce a negotiate inside the square root.
Set y=0
And square both side to cancel the sqrt
3x-8=0
And solve for x
X=8/3
So therefore x>= 8/3
And the domain is { x E R >= 8/3 }
Btw E is meant to be the epsilon
Set y=0
And square both side to cancel the sqrt
3x-8=0
And solve for x
X=8/3
So therefore x>= 8/3
And the domain is { x E R >= 8/3 }
Btw E is meant to be the epsilon
The domain of the function is x ≥ ( 8/3).
What is a domain?
The domain of the function is defined as the set of all the possible values of the function.
You cannot have a square of a negative so you have to see what values of x would not produce a negotiation inside the square root.
Set y=0, and square both sides to cancel the square root.
3x-8=0
x=8/3
Therefore, the domain of the function is x ≥ ( 8/3).
To know more about the domain follow
https://brainly.com/question/2264373
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