Respuesta :

You cannot have a square of a negative so you have to see what values of x would not produce a negotiate inside the square root.

Set y=0
And square both side to cancel the sqrt
3x-8=0
And solve for x
X=8/3

So therefore x>= 8/3
And the domain is { x E R >= 8/3 }

Btw E is meant to be the epsilon

The domain of the function is x ≥ ( 8/3).

What is a domain?

The domain of the function is defined as the set of all the possible values of the function.

You cannot have a square of a negative so you have to see what values of x would not produce a negotiation inside the square root.

Set y=0, and square both sides to cancel the square root.

3x-8=0

x=8/3

Therefore, the domain of the function is x ≥ ( 8/3).

To know more about the domain follow

https://brainly.com/question/2264373

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