Question

Help Plz!

Simplify:

$\frac{2\sqrt[3]{9}}{1+\sqrt[3]{3}+\sqrt[3]{9} }$

Answer 1

Answer and step-by-step explanation:

Rewrite 9 as 3^2

= 2*$\sqrt[3]{3^{2} }$ / 1 + $\sqrt[3]{3} +\sqrt[3]{3^{2} }$

= 2*$3^{\frac{2}{3} }$/ 1 + $\sqrt[3]{3}$ + $3^{\frac{2}{3} }$

And it would be approximately 0.92

Hope this help you :3