Answer:
see below
Step-by-step explanation:
For problems of this nature, it is convenient to use a spreadsheet to do the calculations. At each stage, the next value of y is ...
y[n] = y'·Δx + y[n-1] . . . . where ∆x is the step size, and y[n-1] is the previous value of y, the same value that goes into the calculation of y'.
Of course, y' is given by the equation in the problem statement.
We are given ...
y0 = 0 . . . for x=2
Then ...
y1 = (0 -3(2))·0.5 + 0 = -3
y2 = (-3 -3(2.5))·0.5 + (-3) = -8.25
and so it goes.
The numbers listed in the "y" column in the attached spreadsheet are y0 through y4 rounded to 2 decimal places. (Calculations are carried to full precision.)
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Calculation Simplified
For the given step size, the calculation can be simplified to ...
y[n] = 1.5(y[n-1] -x[n-1])
so, ...
y3 = 1.5(-8.25 -3.0) = -16.875
y4 = 1.5(-16.875 -3.5) = -30.5625
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Actual Solution
The actual solution to this differential equation is ...
y = 3(1+x) -9e^(x-2)
The spreadsheet also shows the actual value of y and the percentage error in the estimate with the given step size. Changing the step size to 0.02 reduces the error to less than 3% over the same x-interval [0, 4]. Of course, many more steps are required.
