Answer:
The speed of the galaxy A moving according to an observer in galaxy B is 0.95c.
Explanation:
Given that,
Speed = 0.85c
Let [tex]v_{AB}[/tex] is the velocity of galaxy A relative to galaxy B, [tex]v_{AE}[/tex] is velocity of galaxy A relative to Earth and [tex]v_{EB}[/tex] velocity of Earth relative to galaxy B.
Let’s assume that galaxy A is moving to the right,along the +x direction, so its velocity relative to earth is [tex]v_{AE}=0.85c[/tex]
Galaxy B is moving along the–x axis with a speed of 0.55c relative to earth, so its velocity is [tex]v_{BE}=0.55c[/tex]
Using velocity additional formula
[tex]v_{EB}=-(-0.55c)[/tex]
We need to calculate the velocity of the galaxy A relative to galaxy B
Using formula of relative velocity
[tex]v_{AB}=\dfrac{v_{AE}+v_{EB}}{1+\dfrac{V_{AE}V_{EB}}{c^2}}[/tex]
[tex]v_{AB}=\dfrac{0.85+0.55}{1+\dfrac{0.75c\times0.55c}{c^2}}[/tex]
[tex]v_{AB}=c\dfrac{0.85+0.55}{1+0.4675}[/tex]
[tex]v_{AB}=0.95c[/tex]
Hence, The speed of the galaxy A moving according to an observer in galaxy B is 0.95c.