Question

According to one estimate, the first atomic bomb released an energy equivalent to 20 kilotons of TNT. If 1 ton of TNT releases about 4.0 109 J, how much uranium was lost through fission in this bomb? (Assume 208 MeV released per fission.)

Answer 1

Answer:

The uranium was lost through fission in this bomb is 941 gm.

Explanation:

Given that,

Total Energy released from 20 kilotons of TNT is

We need to calculate the total energy

$E_{t}=4.0\times10^{9}\times20\times10^{3}$

$E_{t}=8\times10^{13}\ J$

Energy released by 1.0 gm of U-235 is

$E=\dfrac{Nm}{M}$

Put the value into the formula

$E=\dfrac{6.023\times10^{23}\times208\times1.6\times10^{-13}}{235}$

$E=8.5\times10^{10}\ J$

Mass of U-235 released in this reaction is

$m=\dfrac{E_{total}}{E}$

$m=\dfrac{8\times10^{13}}{8.5\times10^{10}}$

$m=941\ gm$

Hence, The uranium was lost through fission in this bomb is 941 gm.