Answer:
0, π, 7π/6, 11π/6, 2π.
Step-by-step explanation:
sin Ф + 1 = cos 2Ф using the identity cos2x = 1 - 2sin^2 x:
sin Ф + 1 = 1 - 2sin^2 Ф
2sin^2 Ф + sin Ф + 1 - 1 = 0
2sin^2 Ф + sin Ф = 0
sin Ф(2 sin Ф + 1 = 0
sin Ф = 0, sin Ф= -1/2
This gives Ф = 0, π, 2π, 7π/6, 11π/6.
