Answer:
it is correct that electric field decreases by 1/r²
Explanation:
as we know the strength of electric field is calculated by
[tex]E = \dfrac{F}{q}[/tex]
[tex]E = \dfrac{k . Q}{r^2}[/tex]
so electric field at r = 0.5 m
[tex]E = \dfrac{k . Q}{0.5^2}[/tex]
[tex]E = 4 k . Q[/tex]
so electric field at r = 1 m
[tex]E = \dfrac{k . Q}{1^2}[/tex]
[tex]E =k . Q[/tex]
by moving from 0.5 to 1 electric field strength decrease by 4 times
hence, it is correct that electric field decreases by 1/r² = 1/0.5² = 4