Measure the strength of the electric field 0.5 m directly above the midpoint as well as 1 m directly above. Does the strength of the electric field decrease as 1 over distance squared (1/r2)?

Respuesta :

Answer:

it is correct that electric field decreases by 1/r²

Explanation:

as we know the strength of electric field is calculated by

             [tex]E = \dfrac{F}{q}[/tex]  

             [tex]E = \dfrac{k . Q}{r^2}[/tex]

so electric field at r = 0.5 m

              [tex]E = \dfrac{k . Q}{0.5^2}[/tex]

              [tex]E = 4 k . Q[/tex]

so electric field at r = 1 m

              [tex]E = \dfrac{k . Q}{1^2}[/tex]

               [tex]E =k . Q[/tex]

by moving from 0.5 to 1 electric field strength decrease by 4 times

hence, it is correct that electric field decreases by 1/r² = 1/0.5² = 4