[tex]\vec r(x,y,z)=x\,\vec\imath+y\,\vec\jmath+z\,vec k[/tex]
[tex]\vec F(\vec r)=\dfrac{cx\,\vec\imath+cy\,\vec\jmath+cz\,\vec k}{(x^2+y^2+z^2)^{3/2}}[/tex]
[tex]\vec F[/tex] has divergence 0, so the flux of [tex]\vec F[/tex] across a sphere of any radius will always be 0 and thus independent of the sphere's radius.