Answer:
Step-by-step explanation:
Given that for a sample of size n = 13, mean =122 and std dev = 13
STd error of sample = [tex]\frac{13}{\sqrt{13} } =3.61[/tex]
Hypotheses:
[tex]H_0: x bar = 121\\H_a: x bar >121[/tex]
(One tailed test at 5% sign level)
Mean difference = 1 and test statistic
[tex]t = \frac{1}{3.61} \\=0.2778[/tex]
df = n-1 =12
pvalue = 0.3929
Since p > alpha, accept null hypothesis
There is no evidence to prove that mean is greater than 121.