Answer:
[tex]\boxed{\text{4 oz}}[/tex]
Explanation:
1. Energy needed
[tex]\text{Energy} = \text{1 kWh} \times \dfrac{\text{3500 BTU}}{\text{1 kWh}} = \text{3500 BTU}[/tex]
2. Mass of coal needed
[tex]\text{Mass of coal} = \text{3500 BTU} \times \dfrac{\text{1 lb coal}}{\text{14 000 BTU}} = \text{0.25 lb coal} = \textbf{4 oz coal}\\\\\text{It takes $\boxed{\textbf{4 oz of coal}}$ to produce 1 kWh of electricity}[/tex]