Write the ratios for sin X and cos X.
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Answer: First Option
[tex]sin(X)=\frac{\sqrt{119}}{12}[/tex], [tex]cos(X)=\frac{5}{12}[/tex]
Step-by-step explanation:
We know that the sine function is defined as:
[tex]sin(x)=\frac{Opposite}{Hypotenuse}[/tex]
In the same way the cosine function is defined as:
[tex]cos(x)=\frac{adjacent}{Hypotenuse}[/tex]
Therefore it is fulfilled that:
Opposite: is the length of the side opposite angle
Adjacent: It is the length of the side that contains the angle of 90 ° and angle
Hypotenuse: It is the length of the side opposite the angle of 90 °
So for angle X:
[tex]Opposite=\sqrt{119}[/tex]
[tex]Adjacent=5[/tex]
[tex]Hypotenuse=12[/tex]
Finally:
[tex]sin(X)=\frac{\sqrt{119}}{12}[/tex]
[tex]cos(X)=\frac{5}{12}[/tex]