Question

Points j, k, and L are collinear

Answer 1

Answer:

n=4

JK=12

KL=13

Step-by-step explanation:

Given information: JK=3n and KL=5n-7.

It is given that Points J, K, and L are collinear. It means points J, K and L lie on a straight line.

Using segment addition property we get

$JL=JK+KL$

$JL=3n+5n-7$

$JL=8n-7$

(a)

It is given that JL=25.

$25=8n-7$

Add 7 on both sides.

$32=8n$

Divide both sides by 8.

$\frac{32}{8}=n$

$4=n$

Therefore, the value of n is 4.

(b)

$JK=3n$

$JK=3(4)$

$JK=12$

The value of JK is 12 units.

$KL=5n-7$

$KL=5(4)-7$

$KL=20-7$

$KL=13$

Therefore the value of KL is 13 units.

Answer 2

Using simple algebra we can see that:

a) n = 4

b) JK = 12

    KL = 13

How to find the length of the segment?

We know that J, K, and, L are collinear, this means that:

JK + KL = JL

a) If JL = 25, then:

JK + KL = 25

Replacing the equations we get:

3n + 5n - 7 = 25

8n - 7 = 25

8n = 25 + 7 = 32

n = 32/8 = 4

n = 4

b) JK is the segment from J to K, the one that measures 3n, and n is equal to 4, then:

JK = 3*4 = 12

KL is the segment that measures 5n - 7, replacing the value of n we get:

KL = 5*4 - 7 = 13

If you want to learn more about segments, you can read:

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