Question

What is Keq for the reaction 2HCl(9) = H2(g) + Cl2(9)?

Answer 1

Answer:

Keq = ( [ H2(g) ] * [ Cl2(g) ] ) / [ HCl(g) ]²

Explanation:

from de la reaction:

• 2HCl(g) ↔ H2(g) + Cl2(g)

⇒ Keq = ( [ H2(g) ] * [ CL2 ](g) ) / [ HCl(g) ]²

Answer 2

Answer: The expression of $K_{eq}$ is written below.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For a general chemical reaction:

$aA+bB\rightarrow cC+dD$

The expression for $K_{eq}$ is written as:

$K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

Concentration of solid and liquid substances in a chemical reaction is taken to be 1.

For the given chemical equation:

$2HCl(g)\rightleftharpoons H_2(g)+Cl_2(g)$

The expression of $K_{eq}$ for the above equation follows:

$K_{eq}=\frac{[Cl_2]\times [H_2]}{[HCl]^2}$

Hence, the expression of $K_{eq}$ is written above.