Respuesta :

gmany

Answer:

[tex]\large\boxed{\dfrac{1}{5\cdot5\cdot5\cdot5\cdot5\cdot5}}[/tex]

Step-by-step explanation:

[tex]\text{Use}\ (a^n)^m=a^{nm}\\\\(5^3)^{-2}=5^{(3)(-2)}=5^{-6}\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{1}{5^6}\\\\\text{use}\ a^n=\underbrace{a\cdot a\cdot a\cdot ...\cdot a}_{n}\\\\=\dfrac{1}{5\cdot5\cdot5\cdot5\cdot5\cdot5}[/tex]

ACCESS MORE