Respuesta :
Answer:
a. 1
Step-by-step explanation:
[tex](a-b)^2=a^2-2ab+b^2\\\\\text{We have}\ x^2-2x+c=x^2-2(x)(1)+c.\\\\\text{Therefore}\ c=1^2=1\\\\x^2-2(x)(1)+1^2=(x-1)^2[/tex]
Answer:
a
Step-by-step explanation:
Given
x² - 2x + c
is a perfect square of the form
(x - a)² = x² - 2ax + a² compare with x² - 2x + c, then
- 2a = - 2 ⇒ a = 1, thus
a² = 1² = 1 = c
(x - 1)² = x² - 2x + 1 ← perfect square trinomial