Question

Let f(x) = 8x3 + 18x2 − 10 and g(x) = 4x + 1. Find f of x over g of x.

2 times x squared plus 4 times x minus 1 plus 9 over the quantity 4 times x plus 1

2 times x squared plus 4 times x minus 1 minus 9 over the quantity 4 times x plus 1

2 times x squared plus 4 times x plus 1 plus 9 over the quantity 4 times x plus 1

2 times x squared plus 4 times x plus 1 minus 9 over the quantity 4 times x plus 1

Answer 1

Answer:

all is shown in the picture above

Answer 2

For this case we have the following functions:

$f (x) = 8x ^ 3 + 18x ^ 2-10\\g (x) = 4x + 1$

We must find the value of the following expression:

$\frac {f (x)} {g (x)}$

So:$\frac {f (x)} {g (x)} = \frac {8x ^ 3 + 18x ^ 2-10} {4x + 1}$

According to the attached figure we have to:

$\frac {f (x)} {g (x)} = 2x ^ 2 + 4x-1- \frac {9} {4x + 1}$

Answer:

$\frac {f (x)} {g (x)} = 2x ^ 2 + 4x-1- \frac {9} {4x + 1}$

Opcion B