Answer:
There are 11 pennies and 41 dimes in the cup.
Step-by-step explanation:
Let the pennies be represented by = p
Let the dimes be represented by = d
The total value of the coins is $4.21. We get the first equation as:
[tex]0.01p+0.10d=4.21[/tex] .......(1)
The number of dimes is three less than four times the number of pennies. We get the second equation as:
[tex]d=4p-3[/tex] ......(2)
Substituting the value of d from (2) in (1)
[tex]0.01p+0.10(4p-3)=4.21[/tex]
Solving this we get;
[tex]0.01p+0.4p-0.3=4.21[/tex]
=> [tex]0.41p=4.21+0.3[/tex]
=> [tex]0.41p=4.51[/tex]
We get p = 11
And [tex]d=4(11)-3[/tex] = [tex]44-3[/tex]
We get d = 41
Therefore, there are 11 pennies and 41 dimes in the cup.