Question

Owls eat rats, mice, shrews, and small birds. Assume that, over a period of time, an owl consumes 5,000 J of animal material. The owl loses 2,300 J in feces and owl pellets and uses 2,600 J for cellular respiration. What is the production efficiency of this owl

Answer 1

Answer:

The production efficiency of this owl is $4$%

Explanation:

Given -

Energy from food $= 5000$J

Energy lost in feces $= 2300$J

Energy used in cellular respiration (metabolism) $= 2600$J

The production efficiency of consumer in an ecosystem is given by

(Energy from food- Energy lost in feces-Energy used in cellular respiration (metabolism)) divided by (Energy from food- Energy lost in feces)

Substituting the given values in above equation, we get -

$\frac{5000-2300-2600}{5000-2300} *100\\= \frac{100}{2700} *100\\= 3.7\\= 4$%

Hence, the production efficiency of this owl is $4$%

Answer 2

The production efficiency of this owl is : 4%

Given data :

Energy gained by Owl = 5000 J

Energy lost by owl via feces = 2300 J

Energy used for respiration = 2600 J

Determine the production efficiency of the owl

Production efficiency = Energy gained - Energy lost ) /  Energy gained - energy lost via feces  * 100

                                   = ( 5000 - 2300 - 2600 ) / ( 5000 - 2300 ) * 100

                                   = ( 100 / 2700 ) * 100

                                   = 3.7% ≈ 4%.

Therefore we can conclude that The production efficiency of this owl is : 4%

Learn more about production efficiency : https://brainly.com/question/26320301