Answer: The correct answer is [tex]CaCO_3(s)+2H^+(aq.)\rightarrow Ca^{2+}(aq.)+CO_2(g)+H_2O(l)[/tex]
Explanation:
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of sodium bicarbonate and acetic acid is given as:
[tex]CaCO_3(s)+2HCl(aq.)\rightarrow CaCl_2(aq.)+H_2O(l)+CO_2(g)[/tex]
Ionic form of the above equation follows:
[tex]CaCO_3(s)+2Cl^-(aq.)+2H^+(aq.)\rightarrow Ca^{2+}(aq.)+2Cl^-(aq.)+H_2O(l)+CO_2(g)[/tex]
As, chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and is the spectator ion.
The net ionic equation for the above reaction follows:
[tex]CaCO_3(s)+2H^+(aq.)\rightarrow Ca^{2+}(aq.)+CO_2(g)+H_2O(l)[/tex]
Hence, the correct answer is [tex]CaCO_3(s)+2H^+(aq.)\rightarrow Ca^{2+}(aq.)+CO_2(g)+H_2O(l)[/tex]