Answer:
(a) It is a two-tailed test.
(b) The P-value is 0.042357.
(c) Since P-value < α, therefore we reject H₀.
Step-by-step explanation:
Given information: The value of test statistic is z = 2.03.
(a)
We need to test the claim that p≠0.155.
Null hypothesis: [tex]H_0:p=0.155[/tex]
Alternative hypothesis: [tex]H_1:p\neq 0.155[/tex]
It is a two-tailed test.
(b)
The level of significance is α=0.10.
The P-value for a two-tailed test, for a significance level of α=0.10 is 0.042357.
Therefore the P-value is 0.042357.
(c)
If P-value < α, then we reject H₀.
If P-value ≥ α, then we accept H₀.
where, α is level of significance.
It is given that α=0.10. Form part (b) it is clear that the P-value for a two-tailed test, for a significance level of α=0.10 is 0.042357.
0.042357 < 0.10
Since P-value < α, therefore we reject H₀.