Answer:
At 5.38 seconds the ball hits the ground.
Explanation:
It is given that,
The height of the ball after t seconds is given by the formula as :
[tex]h(t)=464-16t^2[/tex]
Where
t is in feet
and height is in feet
When the ball hits the ground, its height is equal to 0. So,
[tex]464-16t^2=0[/tex]
On solving the above equation we get:
t =5.38 seconds
So, at 5.38 seconds the ball hits the ground. Hence, this is the required solution.
