Answer:
20 ounces of 12% solution and 4 ounces of 6% solution.
Explanation:
Let x be the quantity ( in ounces ) of 12% solution that is mixed with y quantity ( in ounces ) of 6% solution to obtain 24 ounces of 11% solution,
∵ Quantity of resultant solution = 24 ounces
⇒ x + y = 24
⇒ x = 24 - y ------(1)
Also, 12% of x + 6% of y = 11% of 24
0.12x + 0.06y = 0.11 × 24
12x + 6y = 264
From equation (1),
12(24-y) + 6y = 264
288 - 12y + 6y = 264
288 - 6y = 264
-6y = 264 - 288
-6y = -24
⇒ y = 4
Again from equation (1),
x = 24 - 4 = 20
Hence, 20 ounces of 12% solution and 4 ounces of 6% solution should mix to get this solution.