Respuesta :
Answer:
The probability that she makes exactly 7 of them is 0.215.
Step-by-step explanation:
It is given that the probability that she makes each shot is 0.6.
The probability of success, p=0.6
The probability of failure, q= 1-p = 1-0.6 = 0.4
Total number of shots = 10.
According to the binomial distribution, the probability of r success in n trial is
[tex]P=^nC_rp^rq^{n-r}[/tex]
where, n is total trials, r is number of success, p is probability of success and q is probability of failure.
The probability that she makes exactly 7 of them is
[tex]P=^{10}C_7(0.6)^7(0.4)^{10-7}[/tex]
[tex]P=\frac{10!}{7!(10-7)!}(0.6)^7(0.4)^{3}[/tex]
[tex]P=0.214990848[/tex]
[tex]P\approx 0.215[/tex]
Therefore the probability that she makes exactly 7 of them is 0.215.
Answer:
The probability that she makes exactly 7 of them is 0.215 in three decimal places.
Step-by-step explanation:
It is given that the probability that jamie makes each shot is 0.6.
The probability of success, p=0.6
While the probability of failure, q= 1-p = 1-0.6 = 0.4
Total number of shots(n) = 10.
According to the binomial distribution, the probability of x success in n trial is
P=nCx((p)^x)((q)^(n-x))
where, n is total trials, x is number of success, p is probability of success and q is probability of failure.
The probability that she makes exactly 7 of them is.
P= 10C7*((0.6)^7) *((0.4)^3)
P= 120*0.0279936*0.064
P= 0.21499
Round up to 3 d.p = 0.215
Therefore the probability that she makes exactly 7 of them to three decimal places is 0.215
