Question

Solve the quadratic equation by completing the square. ATTACHED BELOW!!!!!!NEED HELP FAST!!!!!!!!!!!!!

Answer 1

Answer:

x ≈ 2.76, x ≈ 7.24

Step-by-step explanation:

Given

x² - 10x + 20 = 0 ( subtract 20 from both sides )

x² - 10x = - 20

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2( - 5)x + 25 = - 20 + 25

(x - 5)² = 5 ( take the square root of both sides )

x - 5 = ± $\sqrt{5}$ ( add 5 to both sides )

x = 5 ± $\sqrt{5}$

Hence

x = 5 - $\sqrt{5}$ ≈ 2.76

x = 5 + $\sqrt{5}$ ≈ 7.24

Answer 2

x ≈ 2.76,

x ≈ 7.24

How to quickly solve a quadratic equation?

ax2+c=0 is the pure quadratic equation. To solve it , bring the constant term the RHS (right hand side) or divide both side by a, coefficient of the x2 or take the square root. Bring the equation ax2+c=0 in the form p2-q2 =0. Use the p2-q2= (p+q) (p-q).

How do you solve a quadratic equation?

• Write a equation in the form of, ax2 +bx +c = 0 a x 2 + b x + c = 0
• Factorize the quadratic and solve for a variable.
• Use quadratic formula if we could not factorize the quadratic.
• Quadratic formula: x = −b± b2−4ac√ 2a x = − b ± b 2 − 4 a c 2 a

Step-by-step explanation:

Given

x² - 10x + 20 = 0 ( subtract 20 from both sides )

x² - 10x = - 20

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2( - 5)x + 25 = - 20 + 25

(x - 5)² = 5 ( take the square root of both sides )

x - 5 = ± $\sqrt{5}$ ( add 5 to both sides )

x = 5 ± $\sqrt{5}$

Hence

x = 5 -$\sqrt{5}$  ≈ 2.76

x = 5 +  $\sqrt{5}$≈ 7.24

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