ZC is an altitude, m∠CYW (5x + 22)°, and m∠WZC (12x)°. Find m∠WZC
A) 32 °
B) 45 °
C) 48 °
D) 20 °
![ZC is an altitude mCYW 5x 22 and mWZC 12x Find mWZC A 32 B 45 C 48 D 20 class=](https://us-static.z-dn.net/files/dcb/ee2c61ba0e63eb66676ebd82b93ad983.png)
Answer:
C
Step-by-step explanation:
ZC is an altitude, thus ∠ZCY = 90°
The sum of the3 angles in a triangle = 180°
Sum the 3 angles in ΔCYZ and equate to 180
90 + 5x + 22 + 12x = 180 ← simplify left side
17x + 112 = 180 ( subtract f112 from both sides )
17x = 68 ( divide both sides by 17)
x = 4
Hence
∠WZC = 12x = 12 × 4 = 48° → C
The m∠WZC is 48 degrees.
ZC should be the altitude,
So
∠ZCY = 90°
Now
The sum of the 3 angles in a triangle = 180°
And,
Sum the 3 angles in ΔCYZ and equate to 180
90 + 5x + 22 + 12x = 18
17x + 112 = 180
17x = 68
x = 4
Hence
∠WZC = 12x
= 12(4)
= 48°
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