Question

A tree branch is floating in water. The total volume of the branch is 1.12 m3 and 75.0 percent of the volume is submerged. The density of water is 1000 kg/m3. Find the buoyant force on the branch.

Answer 1

The buoyant force on the branch is given by:
F = pVg
F = buoyant force, p = water density, V = volume of branch submerged, g = gravitational acceleration

Given values:
p = 1000kg/m^3
V = 0.75x1.12m^3 (75% of total volume)
g = 9.81m/s^2

Plug in and solve for F:
F = 1000(0.75x1.12)(9.81)

F = 8240N