Question

PLEASE HELP

prove that for any linear equation, y=mx+b, equal intervals result in growth by equal differences.

Step 1: If the equal interval is k, the two endpoints of the interval will be labeled p and p + k. Label the endpoints of the corresponding interval on the y-axis of the graph below. Hint: First, substitute x=p into y=mx+b. Next, substitute x=p+k into y=mx+b


Step 2: Find the difference between the endpoints of the interval on the y-axis.

(1)
[y-value at x=p]-

(2)
[y-value at x=p+k]

Step 3 Does your answer to Step 2 depend on p?
what does it depend on? is the difference between the y-values the same regardless of where the interval starts?

Answer 1

Answer: Look below

Step-by-step explanation:

Step 1:

1) y-value at x=p is 8

  y-value at x=p+k is 5

(All you have to do is look at the graph)

2) x=p - x= p+k = 8-5= 3

(Subtract 3 from 8 and you get 5)

3) The answer does depend on P because you are dealing with a slope. You endpoints are fixed in a position, so when you go up or down the slope, it will not be the same. I don't think the values will be the same because you are dealing with a slope...

Answer 2

1) y-value at x=p is 8

y-price at x=p+k is 5

(All you have to do is observe the graph)

2) x=p - x= p+k = 8-5= 3

(Subtract 3 from eight and also you get five)

3) The solution does rely on P due to the fact you're handling a slope. Your endpoints are constant in a function, so when you move up or down the slope, it will now not be identical. I do not suppose the values will be the same because you are managing a slope.

What is the linear equation with example?

The standard shape for linear equations in two variables is Ax+by =C. as an example, 2x+3y=5 is a linear equation of a well-known shape. whilst an equation is given in this shape, it's quite easy to find each intercept (x and y). This shape is likewise very useful while fixing systems of two linear equations.

Learn more about Linear equations at https://brainly.com/question/1884491

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