Question

A game is played where players take turns rolling two six-sided dice, each with sides numbered 1-6. The numbers on the two dice are added together for each player's score. If the first player rolls a sum of 10, what is the probability that the second player rolls a HIGHER total?

Answer 1

Answer:

$\frac{1}{12}$

Step-by-step explanation:

Total number of possible outcomes when a dice is rolled six times

$= 6*6\\= 36$

Number of possible outcomes than have a sum greater than 10 are

$(6,5)\\(5,6)\\(6,6)$

Probability that the second player rolls a total higher than 10 is equal to the total number of possible outcomes with sum greater than 10 divided by total outcomes

$\frac{3}{36} \\= \frac{1}{12}$