Question

Light enters an equilateral triangle prism in a direction parallel to one side. The prism is made of glass with an index of refraction of 1.52. What is the angle between the incoming ray and the ray that leaves the prism on the other side?

Answer 1

Answer:

31.2 degree

Explanation:

Angle of prism, A = 60 degree

refractive index, μ = 1.52

The angle between the incident ray and the emergent ray is called angle of deviation δ.

The angle between the ange of deviation and the refractive index is

δ = (μ - 1) A

δ = (1.52 - 1) x 60

δ = 31.2 degree

Answer 2

The angle of minmum deviation is  38°.

What is minimum deviation?

The term minimum deviation refers to the angle at which the incident ray and the emergent ray are both inclined towards each other.

Thus;

n = sin 0.5(A + D)/Sin0.5(A)

Where;

n = refractive index =  1.52

A = refracting angle of the triangular prism = 60°

D = angle of minimum deviation

Substituting values;

1.52 = sin0.5(60 + D)/sin0.5(60)

0.76 = sin0.5(60 + D)

Sin-1(0.76) = 0.5(60 + D)

49 = 0.5(60 + D)

49 = 30 + 0.5D

D = 38°

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