Respuesta :
Answer:
79.1°
Explanation:
Given:
x₀ = 0 m
y₀ = 0 m
x = 19500 cos 32°
y = 19500 sin 32°
v₀x = 1810 cos 20°
v₀y = 1810 sin 20°
t = 9.20
Find:
ax, ay, θ
First, in the x direction:
x = x₀ + v₀ t + ½ at²
19500 cos 32° = 0 + (1810 cos 20°) (9.20) + ½ ax (9.20)²
16537 = 15648 + 42.32 ax
ax ≈ 21.01
And in the y direction:
y = y₀ + v₀ t + ½ at²
19500 sin 32° = 0 + (1810 sin 20°) (9.20) + ½ ay (9.20)²
10333 = 5695 + 42.32 ay
ay ≈ 109.6
The direction of the acceleration is therefore:
θ = atan(ay / ax)
θ = atan(109.6 / 21.01)
θ ≈ 79.1°
Answer:
79.1°
Explanation:
A missile is moving 1810 m/s at a 20.0 degree angle. It needs to hit a target 19,500 m away in a 32 degree direction in 9.20 seconds. The direction of the acceleration that the engine must produce is 79.1°