Answer:
[tex]\boxed{y = -6x - 16}[/tex]
Step-by-step explanation:
The point-slope formula for a straight line is
[tex]y - y_{1} = m(x - x_{1})}[/tex]
x₁ = -2; y₁ = -4; m = -6
Substitute the values
[tex]\begin{array}{rcl}y - (-4) & = & -6(x - (-2))\\y + 4 & = & -6(x + 2)\\y + 4 & = & -6x - 12)\\y & = & -6x - 16\\\end{array}\\\text{The equation for the line is $\boxed{\mathbf{y = -6x - 16}}$}[/tex]
The diagram shows the graph of the equation with slope -6 passing through (-2,--4).
