The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 13.713.7degrees°. If skyscraper B is 14521452 feet tall, how far apart are the two skyscrapers? Assume the bases of the two buildings are at the same elevation.

If we designate the points at the bases of the skyscrapers as A and B, and the top of skyscraper B as point T, then triangle ABT is a right triangle with angle B = 90° and angle A = 13.7°.

The definition of the tangent function tells us ...

tan(A) = BT/AB

Solving for AB, we find ...

AB = BT/tan(A) = (1452 ft)/tan(13.7°)

AB ≈ 5956 ft

The skyscrapers are about 5956 feet apart.

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The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 13.713.7degrees°. If skyscraper B is 14521452 feet​ tall, how far apart are the two​ skyscrapers? Assume the bases of the two buildings are at the same elevation.

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The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 13.713.7degrees°. If skyscraper B is 14521452 feet tall, how far apart are the two skyscrapers? Assume the bases of the two buildings are at the same elevation.