Answer:
Let the distance between woman and pole be "x".
From diagram,
In ΔOAB,
tan 18 = [tex]\frac{Perpendicular}{Base}[/tex]
tan 18 = [tex]\frac{65 -y}{x}[/tex]
∴ x = [tex]\frac{65 -y}{tan 18}[/tex] ................ (1)
In ΔOBC
tan 14 = [tex]\frac{Perpendicular}{Base}[/tex]
tan 14 = [tex]\frac{y}{x}[/tex]
y = x × tan 14 ..............(2)
equating (2) in (1), we get;
x = [tex]\frac{65}{tan 18 + tan 14}[/tex]
x = [tex]\frac{65}{0.574}[/tex]
∵ tan 18 + tan 14 = 0.574
∴ x = 113.2 ft
i.e. The her distance from the pole is 113.2 ft.