Question

Light from a helium-neon laser (wavelength 633 nm) passes through a 0.5 mm diameter hole. How far away should a viewing screen be placed to observe a diffraction pattern whose central maximum is 3.0 mm in diameter ?

Answer 1

Answer:

L = 0.97 m

Explanation:

Given

wavelength of light λ = 633 nm

Diameter of the hole d  = 0.5 mm

Diameter of the central maxima D = 3.0 mm

To find

Distance of the screen  L = ? m

Solution

$D=\frac{2.44 \times \lambda L}{d} \\L= \frac{d \times D}{2.44 \times \lambda} \\L= \frac{0.0005 \times 0.003}{2.44 \times 633 \times 10^{-9} } \\L = 0.97 m$