Answer:
[tex]\frac{x-1}{x^{2} +2x-3}[/tex]
[tex]\frac{1}{x+3}[/tex]
Step-by-step explanation:
first, subtract the two fractions
You will have
[tex]\frac{x-1}{x^{2} +2x-3}[/tex] the un-simplified difference of those expressions
Lets try to simplify that
Lets find the roots of the polynomial from the bottom using the formula for quadratic equation, (-b +/- sqrt( b2-4*a*c)) /(2*a)
Which are x=-3, and x=1
Thus, you have (x+3)*(x-1)
So
[tex]\frac{x-1}{x^{2} +2x-3} = \frac{x-1}{(x+3) (x-1)}= \frac{1}{x+3}[/tex]
