Question

A​ 90% confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is ​(1.4​,4.3​). What is the point estimator of the mean percentage of reservations that are canceled on the day of the​ flight?

Answer 1

Answer: 2.85

Step-by-step explanation:

Given : A​ 90% confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is ​(1.4​, 4.3​) .

We know that the the confidence interval for population mean $\mu$ is given by :-

$\mu\pm E$, where E is the margin of error.

Lower limit of confidence interval = $\mu-E=1.4$          (1)

Upper limit of confidence interval =  $\mu+E=4.3$        (2)

Adding (1) and (2), we get

$2\mu=5.7\\\\\Rightarrow\ \mu=2.85$

Hence, the point estimator of the mean percentage of reservations that are canceled on the day of the​ flight = 2.85