Question

In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres with masses of 1.60 kg and 16.0 g whose centers are separated by about 4.00 cm. Calculate the gravitational force between these spheres, treating each as a particle located at the center of the sphere.

Answer 1

Answer:

$1.0672\times 10^{-9}N$

Explanation:

$G$ = Gravitational constant = 6.67 x 10⁻¹¹

$F$  = Gravitational force between these spheres

$m_{1}$ = mass of first sphere = 1.60 kg

$m_{2}$  = mass of second sphere = 16 g = 0.016 kg

$r$  = distance between the centers of the sphere = 4 cm = 0.04 m

Gravitational force between these spheres is given as

$F = \frac{Gm_{1}m_{2}}{r^{2}}$

$F = \frac{(6.67\times 10^{-11})(1.60)(0.016)}{0.04^{2}}$

$F = 1.0672\times 10^{-9}N$