Answer:
I think it is 3.7E9 years according to the problem.
Explanation:
Here is what I would do.
k = 0.693/t1/2 and solve for k.
Then ln(No/N) = kt
You know k and t, solve for N/No.
If I understand the problem, the current mass U238 is 1.185g.
So you know No/N and N, solve for No which is the amount of U the sample started with. mass U238 initially - mass U today = mass U decayed and convert that to g Pb today.
mass Pb206 today = mass U decayed x (206/238) = ?