Answer: 0.0107
Step-by-step explanation:
Given : The time for the event for boys in secondary school is known to possess a normal distribution with
[tex]\mu=460\text{ seconds}\\\\\sigma=20\text{ seconds}[/tex]
Let x be the random variable that represents the time for mile run in its secondary-school fitness test.
z-score : [tex]\dfrac{x-\mu}{\sigma}[/tex]
[tex]z=\dfrac{322-460}{60}=-2.3[/tex]
Now, the probability that a randomly selected boy in secondary school can run the mile in less than 322 seconds is given by :-
[tex]P(x<322)=P(z<-2.3)=0.0107241\approx0.0107[/tex]
Hence, the probability that a randomly selected boy in secondary school can run the mile in less than 322 seconds = 0.0107