Respuesta :
Answer:
W = 907963.50 J = 907.96 J
Explanation:
Note: Refer to the figure attached
Now, from the figure we have similar triangles ΔAOB and ΔCOD
we have
[tex]\frac{5}{4}=\frac{x}{r}[/tex]
or
[tex]r=\frac{4x}{5}[/tex]
Now, the work done to empty the tank can be given as:
[tex]W = \int\limits^4_0 {(5-x)\rho\times g A} \, dx[/tex]
or
[tex]W = \int\limits^4_0 {(5-x)1080\times 9.8 (\pi r^2)} \, dx[/tex]
or
[tex]W = \int\limits^4_0 {(5-x)\times10584\times (\pi (\frac{4x}{5})^2)} \, dx[/tex]
or
[tex]W = 6773.76\pi\int\limits^4_0 {(5-x)x^2)} \, dx[/tex]
or
[tex]W = 6773.76\pi[\frac{5}{3}x^3-\frac{1}{4}x^4]^4_0 [/tex]
or
[tex]W = 6773.76\pi[\frac{128}{3}] [/tex]
or
W = 907963.50 J = 907.96 J

The work required to empty the tank by pumping the hot chocolate over the top of the tank is 907.96 J.
What is work done?
Work done is the force applied on a body to move it over a distance. The work required to lift a body through a height h is given as,
[tex]W=Fh[/tex]
Here, (F) is the magnitude of force and (f) is the height.
It can be rewritten as,
[tex]W=mgh[/tex]
Here, (m) is the mass of the body.
The tank is in the shape of an inverted right circular cone with height 5 meters and radius 4 meters. As, It is filled with 4 meters of hot chocolate.
Here the ratio of height to radius should be equal to the height at another point (say x), to the radius of that point. Thus,
[tex]\dfrac{5}{4}=\dfrac{x}{r}\\r=\dfrac{4x}{5}[/tex]
For the distance x the work done to empty the cone can be given as,
[tex]W=\int^4_0 (5-x)\rho g \pi r^2 dx\\W=\int^4_0 (5-x)1080\times9.81 \pi (\dfrac{4x}{5})^2 dx\\W=22280.4\int^4_0(5-x)x^2 dx\\W=22280.4[\dfrac{128}{3}]\\W=907.96\rm J[/tex]
Thus, the work required to empty the tank by pumping the hot chocolate over the top of the tank is 907.96 J.
Learn more about the work done here;
https://brainly.com/question/25573309