Respuesta :

Assuming the bus undergoes constant acceleration, it is given by:

a = (Vf-Vi)/Δt

a is the acceleration, Vf is the final velocity, Vi is the initial velocity, and Δt is the elapsed time.

Given values:

Vf = 0m/s (slows to rest)

Vi = 60m/s

Δt = 10s

Plug in the values and solve for a:

a = (0-60)/10

a = -6m/s²

The bus decelerates at a rate of 6m/s².

ACCESS MORE
EDU ACCESS