Answer:
The area of rectangle EFGH is [tex]242\ in^{2}[/tex]
Step-by-step explanation:
For this problem I assume that rectangle ABCD and rectangle EFGH are similar
step 1
Find the scale factor
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor
Let
z ------> the scale factor
The scale factor is the ratio between the diagonals of rectangles
so
[tex]z=\frac{22}{12}=\frac{11}{6}[/tex]
step 2
Find the area of rectangle EFGH
we know that
If two figures are similar, then the ratio of its areas is the scale factor squared
Let
z------> the scale factor
x -----> area of rectangle EFGH
y ----> area of rectangle ABCD
so
[tex]z^{2}=\frac{x}{y}[/tex]
we have
[tex]z=\frac{11}{6}[/tex]
[tex]y=72\ in^{2}[/tex]
substitute and solve for x
[tex](\frac{11}{6})^{2}=\frac{x}{72}[/tex]
[tex]\frac{121}{36}=\frac{x}{72}[/tex]
[tex]x=\frac{121}{36}(72)[/tex]
[tex]x=242\ in^{2}[/tex]