Question

Find the resultant acceleration of a particle moving in a circle of radius 10 cm at the instant when its angular velocity is 6 rad/s and its angular acceleration is 20 rad/s^2.

Answer 1

Answer:

The resultant acceleration of the particle is a= 0.411 m/s²

Explanation:

r= 0.01m

w= 6 rad/s

α= 20 rad/s²

ac= w²*r

ac= 0.36 m/s²

at= α*r

at= 0.2 m/s²

a= √(at² + ac²)

a= 0.411 m/s²