Respuesta :
Answer:
[tex]x^2 + 6x + 34 = (x + 3 + 5i)(x + 3 - 5i)\\x^2 + 16 = (x - 4i)(x + 4i)\\x^2 - 12x + 37 = (x - 6 + i)(x - 6 - i) [/tex]
Step-by-step explanation:
Let us do this starting from the equivalent form
A) [tex](x - 6 + i)(x - 6 - i)[/tex]
Distributing x , -6 and i on the second bracket we get
[tex]x(x - 6 - i)-6(x - 6 - i)+i(x - 6 - i)[/tex]
[tex]x^2-6x-ix-6x+36+6i+xi-6i-i^2[/tex]
replacing [tex]i^2=-1[/tex]
[tex]x^2-6x-6x+36-(-1)[/tex]
[tex]x^2-12x+36+1[/tex]
[tex]x^2-12x+37[/tex]
B) [tex](x + 3 + 5i)(x + 3 - 5i)[/tex]
Distributing x , 3 and 5i on the second bracket we get
[tex]x(x + 3 - 5i)+3(x + 3 - 5i)+5i(x + 3 - 5i)\\x^2+3x-5xi+3x+9-15i+5xi+15i-25i^2\\x^2+3x+3x-5xi+5xi+9-15i+15i-25i^2\\x^2+6x+9-25(-1)\\x^2+6x+9+25\\x^2+6x+34[/tex]
C) [tex](x - 4i)(x + 4i)[/tex]
distributing x and 4i on (x+4i)
[tex]x(x + 4i)-4i(x + 4i)\\x^2+4xi-4xi-16i^2\\x^2-16(-1)\\x^2+16[/tex]
Answer:
(x + 3 + 5i)(x + 3 - 5i)= x^2 + 6x + 34
(x - 4i)(x + 4i)= x^2 + 16
(x - 6 + i)(x - 6 - i)= x^2 - 12x + 37
Step-by-step explanation: just took the test...