Answer:
Part 1) 3 --------> [tex]3\frac{3}{7}[/tex] ÷ [tex]1\frac{1}{7}[/tex]
Part 2) -3 -------> [tex]-2\frac{2}{5}[/tex] ÷ [tex]\frac{4}{5}[/tex]
Part 3) 2 --------> [tex]-12.2[/tex] ÷ [tex]-6.1[/tex]
Part 4) -2 -------> [tex]-16[/tex] ÷ [tex]8[/tex]
Step-by-step explanation:
Part 1) we have
[tex]3\frac{3}{7}[/tex] ÷ [tex]1\frac{1}{7}[/tex]
Convert mixed number to an improper fraction
[tex]3\frac{3}{7}=\frac{3*7+3}{7}=\frac{24}{7}[/tex]
[tex]1\frac{1}{7}=\frac{1*7+1}{7}=\frac{8}{7}[/tex]
Substitute
The quotient is equal to
[tex](\frac{24}{7})/(\frac{8}{7})=\frac{24}{8}=3[/tex]
Part 2)
we have
[tex]-2\frac{2}{5}[/tex] ÷ [tex]\frac{4}{5}[/tex]
Convert mixed number to an improper fraction
[tex]-2\frac{2}{5}=-\frac{2*5+2}{5}=-\frac{12}{5}[/tex]
Substitute
The quotient is equal to
[tex](-\frac{12}{5})/(\frac{4}{5})=-\frac{12}{4}=-3[/tex]
Part 3) we have
[tex]-12.2[/tex] ÷ [tex]-6.1[/tex]
Convert decimal number to an improper fraction
[tex]-12.2=(-12.2)*\frac{10}{10}=-\frac{122}{10}[/tex]
[tex]-6.1=(-6.1)*\frac{10}{10}=-\frac{61}{10}[/tex]
Substitute
The quotient is equal to
[tex](-\frac{122}{10})/(-\frac{61}{10})=\frac{122}{61}=2[/tex]
Part 4) we have
[tex]-16[/tex] ÷ [tex]8[/tex]
Remember that
[tex]-16=-8*2[/tex]
Substitute
The quotient is equal to
[tex](-8*2)/(8)=-2[/tex]
